Need help! What is the area of this triangle? Enter your answer as a decimal in the box round only your final answer to the nearest tenth.

Question

asked Sep 7, 2020 77.6k views

1 Answer

PSR · Answer 1 · 2020-09-13T05:00:00+0000

The answer is:

The area of the triangle is:

Area=13.2cm^(2)

We can solve the problem using the Side-Angle-Side (SAS) method, to calculate the area of a triangle given two sides and a single angle.

The SAS method to calculate the area of a triangle is given by the following the equation:

Area=(abSinC)/(2)

Where,

a and b are the known sides.

C is the known angle

Now, we are given a triangle with the following dimension:

$Side_(a)=7cm\\Side_(b)=8cm\\\alpha=28\°$

Then, using the information and solving we have:

$Area=(7cm*8cm*Sin(28\°))/(2)$

$Area=(56cm^(2)*Sin(28\°))/(2)\\\\Area=(56cm^(2)*0.47)/(2)\\\\Area=(26.32cm^(2))/(2)\\\\Area=13.16cm^(2)$

Hence, the area of the triangle, rounded to the nearest tenth is:

Area=13.2cm^(2)

Have a nice day!