Answer:
![1.38(g)/(cm^3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q0id0n97hqhppaq448l6yut8su6ptk7mb9.png)
Explanation:
You need to remember the formula for calculate the density:
![density=(mass)/(volume)](https://img.qammunity.org/2020/formulas/physics/middle-school/t3tsop0rpdnq7bxrlzlf2g7x1a3w07j6ti.png)
In this case:
![density_((rock))=(mass_((rock)))/(Volume_((rock)))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qn8ufnokdplqpmz93qwp9ip92k3zpc3s62.png)
You know that:
![mass_((rock))=15.5g](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zqrkalvz1mn06j8f1aknuy7ng68gamdgdp.png)
And when it is placed in a graduated cylinder, the volume is displaced from 25.0 mL to 36.2 mL.
Then, the volume of the rock is:
![Volume_((rock))=36.2mL-25.0mL=11.2mL](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jcc78cro2mx3w40g5sx8hu9bw7n3cu4xes.png)
Since
, you can rewrite the volume as:
Substituting values into the formula, you get that the density of the rock is:
![density_((rock))=(15.5g)/(11.2cm^3)=1.38(g)/(cm^3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8wjpy187nbq2w7e5vj387zimi37s4yfryo.png)