Question

Please help ASAP!!!!!​

Answer 1

Answer: OPTION C

Explanation:

Complete the square:

Having the equation in the form
`ax^2+bx=c`, you need to add
`((b)/(2))^2` to both sides of the equation:

You can identify that "b" in the equation
`x^2+6x=5` is:

`b=6`

Then:

`((6)/(2))^2=3^2`

Add this to both sides:

`x^2+6x+3^2=5+3^2`

Rewriting, you get:

`(x+3)^2=14`

Solve for "x":

`x+3=\±√(14)\\\\x+3=\±√(14)\\\\x=\±√(14)-3`

Then, the solutions are:

`x=-3+√(14)\ or\ x=-3-√(14)`