Answer:
d
Explanation:
let vector A=2i+3j+k and vector B=2i-3j-k
so
vec A. vec B=ABcos¤
(2i+3j+k)(2i-3j-k)=(4+9+1)^1/2 ×(4+9+1)^1/2 ×cos¤
4-9-1=14 cos¤
-6/14=cos¤
¤=cos^-1(-3/7)
The angle between the given vectors is 115.37°.
So the answer is d) None.
It is solved in the given picture.
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