184k views
4 votes
Find the equation in standard form of the line parallel to y=-1/5x+7 and passing through the point (-10,-3)

1 Answer

1 vote

Answer:

the desired equation is y = (-1/5)x - 5.

Explanation:

Parallel lines have the same slope. Here that slope is -1/5.

Let's use the slope-intercept form of the equation of a straight line:

y = mx + b

We know this new line passes through (-10, -3). Substitute -3 for y in y = mx + b, as well as -10 for x and -1/5 for m:

-3 = (-1/5)(-10) + b and solve for b:

-3 = 2 + b. Then b = -5, and the desired equation is y = (-1/5)x - 5.

User Jackytse
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories