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Find the equation in standard form of the line parallel to y=-1/5x+7 and passing through the point (-10,-3)

1 Answer

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Answer:

the desired equation is y = (-1/5)x - 5.

Explanation:

Parallel lines have the same slope. Here that slope is -1/5.

Let's use the slope-intercept form of the equation of a straight line:

y = mx + b

We know this new line passes through (-10, -3). Substitute -3 for y in y = mx + b, as well as -10 for x and -1/5 for m:

-3 = (-1/5)(-10) + b and solve for b:

-3 = 2 + b. Then b = -5, and the desired equation is y = (-1/5)x - 5.

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