Answer:
The sequence is not a geometric sequence
Explanation:
In a geometric sequence you find the following term multiplying the current by a fixed quantity called the common ratio.
To prove if a sequence is geometric we need to check if the ratio is consistent across the sequence. To check for the ratio we use the formula:
![r=(a_n)/(a_(n-1))](https://img.qammunity.org/2020/formulas/mathematics/high-school/hyi7sugruy214sfxmx8qnjvvtc4eukv7it.png)
were
is the ratio
is the current term
is the previous term
Let's star with 1, so
and
![a_(n-1)=-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k94f5ckb7r7bl4lgs8jrj24rqhkortcnsk.png)
![r=(a_n)/(a_(n-1))](https://img.qammunity.org/2020/formulas/mathematics/high-school/hyi7sugruy214sfxmx8qnjvvtc4eukv7it.png)
![r=(1)/(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2tltnxchp0jfq5ptjtnsercrw1geflfwbj.png)
.
Now let's check 4 and 1, so
and
![a_(n-1)=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x64i5f3bc76bu2fa7tk8sbs3zaqrtc3mdy.png)
![r=(a_n)/(a_(n-1))](https://img.qammunity.org/2020/formulas/mathematics/high-school/hyi7sugruy214sfxmx8qnjvvtc4eukv7it.png)
![r=(4)/(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ao4d325uk3sl9gd9tbahpzwa5vomexqcuj.png)
![r=4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bvxzxyzm9j79om6s2uu3ln5pc4ywsksl8e.png)
Since the ratios between two pair of numbers are different, we can conclude that the sequence is not geometric.