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Which of the following is a valid comparison between the possible minimum and maximum values of the function y = -x2 + 4x - 8 and the graph below?

The maximum value of the equation is 1 less than the maximum value of the graph.
The minimum value of the equation is 1 less than the minimum value of the graph.
The minimum value of the equation is 1 greater than the minimum value of the graph.
The maximum value of the equation is 1 greater than the maximum value of the graph.

Which of the following is a valid comparison between the possible minimum and maximum-example-1

2 Answers

4 votes

Answer:

The maximum value of the equation is 1 less than the maximum value of the graph

Explanation:

User Dboswell
by
7.6k points
7 votes

Answer:

The maximum value of the equation is 1 less than the maximum value of the graph

Explanation:

We have the equation
y=-x^2+4x-8.

We can know that this graph will have a maximum value as this is a negative parabola.

In order to find the maximum value, we can use the equation
x=(-b)/(2a)

In our given equation:

a=-1

b=4

c=-8

Now we can plug in these values to the equation


x=(-4)/(-2) \\\\x=2

Now we can plug the x value where the maximum occurs to find the max value of the equation


y=-(2)^2+4(2)-8\\\\y=-4+8-8\\\\y=-4

This means that the maximum of this equation is -4.

The maximum of the graph is shown to be -3

This means that the maximum value of the equation is 1 less than the maximum value of the graph

User Tim Clemans
by
7.5k points

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