Answer:
The equation of the curve is y = x² + 3x
Explanation:
I get your drift, but wish you had stated specifically that you wanted to find the equation of this curve.
Slope of tangent line to curve is dy/dx = 2x + 3.
Integrating that with respect to x yields y = x² + 3x + C.
The point (-3, 0) must satisfy this equation:
0 = (-3)² + 3(-3) + C, so C = 0.
The equation of the curve is y = x² + 3x