Answer:
The approximate lateral area of the prism is

Explanation:
we know that
The lateral area of the prism is equal to

where
P is the perimeter of the base of the prism
H is the height of the prism
Find the perimeter of the hexagonal base
Remember that the area of the hexagonal base is equal to

where
P is the perimeter
a is the apothem
we have


substitute and solve for P


Find the lateral area

we have


substitute the values
