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Write a recursive formula for an, the nth term of the sequence 1, -2, -5,…

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We need two things to write the recursive formula

  • The first term,
    a
  • The common difference,
    d


a is the first value of this sequence. For this set of values,
a = 1, since
1 appears first.


d, the common difference, is
d = t_(3) - t_(2) = t_(2) - t_(1). Basically it's just the the higher term minus the previous terms. To solve for
d,


  • d = t_(3) - t_(2) = -5 - (-2) = -5 + 2 = -3

  • d = t_(2) - t_(1) = -2 - 1 = -3

So regardless of what terms you choose, the common difference will be the same. Now the general formula for a recursive function is


  • t_(n) = a + (n - 1)d

where
n is the
nth term. Let's substitute for
a and
d in this formula.


t_(n) = 1 + (n - 1) * -3\\t_(n) = 1 + -3(n - 1)\\t_(n) = 1 - 3(n - 1)

So the recursive formula is
t_(n) = 1 - 3(n -1)

User Ivan Grishaev
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