Answer:
v = 1630 m/s
T = 5.78 x 10^5 s
Step-by-step explanation:
The tangential speed of the satellite can be found by requiring that the gravitational force on the satellite is equal to the centripetal force:

where
G is the gravitational constant
M=5.97 x 1024kg is the Earth's mass
m is the satellite's mass
is the Earth's radius
is the altitude of the satellite
v is the speed of the satellite
Solving for v,

And the period of the orbit is equal to the ratio between the distance covered during one revolution (the circumference of the orbit) and the speed:

So the correct answer is
v = 1630 m/s
T = 5.78 x 10^5 s