Answer:
higher frequency; shorter wavelength
Step-by-step explanation:
As we know that by Doppler's effect of sound we have a formula of apparent frequency observed by stationary observer when source is coming closer to it is given by

now when source will come closer to stationary observer than the apparent frequency observed by the observer will be greater than the actual frequency heard by the driver
now we also know that the formula for wavelength is given by

so here the wavelength will be smaller by that observer as frequency will be more.
so correct answer will be
higher frequency; shorter wavelength