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There are 3 denominations of bills in a wallet: $1, 5$, and $10. There are five fewer $5-bills than $1-bills. There are half as many $10-billsas $5-bills. If there are $115 altogether, find the number of each type of bill in the wallet.

User Januw A
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1 Answer

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30 votes

Answer:

15 $1 bills

10 $5 bills

10 $10 bills

Explanation:

Let x = number of $1 bills

"There are five fewer $5-bills than $1-bills."

The number of $5 bills is x - 5

"There are half as many $10-bills as $5-bills."

The number of $10 bills is (x - 5)/2.

A $1 bill is worth $1.

x $1 bills are worth x × 1 = x dollars

A $5 bill is worth $5.

x - 5 $5 are worth 5(x - 5) dollars.

A $10 bill is worth $10.

(x - 5)/2 $10 bills are worth 10(x - 5)/2 = 5(x - 5) dollars.

Now we add the value of each type of bills and set it equal to $115.

x + 5(x - 5) + 5(x - 5) = 115

x + 10(x - 5) = 115

x + 10x - 50 = 115

11x = 165

x = 15

There are 15 $1 bills.

$5 bills: x - 5 = 10 - 5 = 10

There are 10 $5 bills

$10 bills: (x - 5)/2 = (15 - 5)/2 = 5

There are 5 $10 bills

Answer: 15 $1 bills; 10 $5 bills; 10 $10 bills

Check:

First, we check the total value of the bills.

15 $1 bills are worth $15

10 $5 bills are worth $50

10 $10 bills are worth $50

$15 + $50 + $50 = $115

The total does add up to $115.

Now we check the numbers of bills of each denomination.

The number of $1 is 15.

The number of $5 is 5 fewer that 15, so it is 10.

The number of $10 bills is half the number of $5 bills, so it is 5.

All the given information checks out in the answer. The answer is correct.

User Antoine Xevlabs
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