Question

the length of a new rectangular playing field is 3 yards longer than quadruple the width. if the perimeter of the rectangular playing field is 586 yards, what are its dimensions?

Answer 1

length = 235 yd

width = 58 yd

Explanation:

Let the width be W.

L = 4W + 3

perimeter = 2(L + W)

perimeter = 2(4W + 3 + W)

perimeter = 2(5W + 3) = 10W + 6

We are told the perimeter = 586 yd

10W + 6 = 586

10W = 580

W = 58

L = 4W + 3 = 4(58) + 3 = 232 + 3 = 235

length = 235 yd

width = 58 yd