Question

I DONT UNDERSTAND!!!!

Answer 1

`\boxed{\text{311 K}}`

Step-by-step explanation:

We can use the Ideal Gas Law and solve for T.

pV = nRT

Data:

p = 0.998 atm

V = 1.20 L

n = 0.0470 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

Calculation:

0.998 × 1.20 = 0.0470 × 0.082 06 × T

1.198 = 0.003 857T

`T = (1.198)/(0.003 857) = \textbf{311 K}`

The Kelvin temperature is
`\boxed{\textbf{311 K}}`, not 307 K.

I suppose you could choose the last square, as it has the closest value.