Find the equation of the circle with center at (3, -2) and radius of 3.

Question

asked Apr 7, 2020 127k views

2 Answers

Manuel Van Rijn · Answer 1 · 2020-04-14T14:38:28+0000

Answer:

(x-3)^(2) +(y+2)^(2)=9

Explanation:

we know that

the equation of a circle into center radius form is equal to

(x-h)^(2) +(y-k)^(2)=r^(2)

In this problem we have

center ( 3,-2)

radius r=3 units

substitute

(x-3)^(2) +(y+2)^(2)=3^(2)

(x-3)^(2) +(y+2)^(2)=9