Question

Find the equation of the circle with center at (3, -2) and radius of 3.

Answer 1

Answer: A on edg

Explanation:

Answer 2

`(x-3)^(2) +(y+2)^(2)=9`

Explanation:

we know that

the equation of a circle into center radius form is equal to

`(x-h)^(2) +(y-k)^(2)=r^(2)`

In this problem we have

center ( 3,-2)

radius r=3 units

substitute

`(x-3)^(2) +(y+2)^(2)=3^(2)`

`(x-3)^(2) +(y+2)^(2)=9`