Answer:
![\text{sin}(B)=(7)/(25)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8p2266fhva9esym10z3fgsr2ohuegsenpu.png)
![\text{tan}(B)=(7)/(24)](https://img.qammunity.org/2020/formulas/mathematics/high-school/eck0x4cr0ya00vn09rbx0ch40b9c51tlqa.png)
Explanation:
We have been given a right triangle. We are asked to find the
and
for our given triangle.
We know that sine relates opposite side of right triangle to its hypotenuse.
![\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/jzyf1omjxhk31eyvht0wkef4hfelozmcw1.png)
We can see that AC is opposite side to angle B and AB is hypotenuse of the given triangle.
![\text{sin}(B)=(AC)/(AB)](https://img.qammunity.org/2020/formulas/mathematics/high-school/mhygqp5bhnxh2fql78wt9gqa2b4tdv1qmn.png)
![\text{sin}(B)=(7)/(25)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8p2266fhva9esym10z3fgsr2ohuegsenpu.png)
We know that tangent relates opposite side of right triangle to its adjacent.
![\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/vu9ms7dwdw1ted831gzfm75pizywkaft5e.png)
We can see that AC is opposite side to angle B and BC is adjacent side of the angle B.
![\text{tan}(B)=(AC)/(BC)](https://img.qammunity.org/2020/formulas/mathematics/high-school/c256vovb3wgyz7bad14j9s0bqobbolpgev.png)
![\text{tan}(B)=(7)/(24)](https://img.qammunity.org/2020/formulas/mathematics/high-school/eck0x4cr0ya00vn09rbx0ch40b9c51tlqa.png)