Answer:
The discriminant is equal to −16, which means the equation has no real number solutions.
Explanation:
![\text{Given the quadratic equation }-1=5x^2-2x](https://img.qammunity.org/2020/formulas/mathematics/high-school/1fz0hplpu9vkbnompg8v3tn5gt5i6nopfb.png)
we have to find the number of real number solutions the equation has.
The equation is
![5x^2-2x+1=0](https://img.qammunity.org/2020/formulas/mathematics/high-school/w59gzb2dumcwhfczh1mld6v0kye5wrcim8.png)
![\text{Comparing above equation }ax^2+bx+c=0](https://img.qammunity.org/2020/formulas/mathematics/high-school/9d2ei8uv82hi5ptcooavqzo9zx5pzus2iz.png)
a=5, b=-2, c=1
To find number of real solutions we have to find the discriminant
![D=b^2-4ac](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m6hc4jrsclve3ufwkeqspgpvwrc0ui7ewj.png)
![D=(-2)^2-4(5)(1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/irs0x539vjsoelsowbll7bypbwhp9r9qud.png)
![D=4-20=-16](https://img.qammunity.org/2020/formulas/mathematics/high-school/x49ysbt8yzibo72uzc1mvvirede5pd5hin.png)
The value of discriminant is -16<0
Hence, the equation has no real roots.
Hence, option 1 is correct