Answer:
Here's a possible example:
Explanation:
![f(x) =\begin{cases} x & \quad x < 3\\x+3 & \quad x \geq 3\\\end{cases}](https://img.qammunity.org/2020/formulas/mathematics/high-school/poutqnjcozo9fwugc6bpugmg15b61xtpy3.png)
Each piece is linear, so the pieces are continuous by themselves.
We need consider only the point at which the pieces meet (x = 3).
![\displaystyle \lim_(x \longrightarrow 3^(-)) f(x) = \lim_(x \longrightarrow 3^(-)) x = 3\\\\\displaystyle \lim_(x \longrightarrow 3^(+)) f(x) = \lim_(x \longrightarrow 3^(+)) x+3 = 6\\\\f(3) = x + 3 = 6\\\\\displaystyle \lim_(x \longrightarrow 3^(-)) f(x) \\eq f(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/52iurm5tqu3zeo80qml5c228rqeejn7o7j.png)
The left-hand limit does not equal ƒ(x), so there is a jump discontinuity at x =3.