235k views
2 votes
2log2-3log2=log2x

I need to show work, please show how to do it

User MyStream
by
7.2k points

1 Answer

2 votes

Answer:

x =
(1)/(4)

Explanation:

Using the rules of logarithms

• log
x^(n) ⇔ n logx

• logx - logy = log(
(x)/(y))

• logx = logy ⇔ x = y

Given

2log2 - 3log2 = log2x

log2² - log2³ = log2x

log4 - log8 = log2x

log
(4)/(8) = log2x, hence

2x =
(1)/(2)

x =
(1)/(4)

User Hatboyzero
by
6.7k points