Question

Need help please.

A point is chosen at random in the square.
What percent of the time will the point be in the circle?
Round to the nearest tenth of a percent.

Answer 1

78.5%

Explanation:

The area of the square is equal to diameter squared

i.e 4 in × 4 in = 16 square inches

The area of the circle is π × r²

i.e π × 2² = 12.56637061

The percent of the time the point will be in the circle = (Area of the circle) ÷ (Area of the square) × 100

i.e
`(12.56637061)/(16)` × 100 = 78.53981631%

And is equal to 78.5% (rounded up to the nearest tenth of a percent)