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Help me please asappp!!!!​

Help me please asappp!!!!​-example-1

2 Answers

3 votes

Answer:

For the function
y=2x^2:


y=0\\y=2\\y=8

For the second function
y=2^x:


y=1\\y=2\\y=4

Explanation:

You only need to make the following substitution:

For the first function
y=2x^2:

When
x=0


y=2x^2\\ y=2(0)^2\\ y=0

When
x=1


y=2(1)^2\\ y=2(1)^2\\ y=2

When
x=2


y=2x^2\\ y=2(2)^2\\ y=2*4\\ y=8

For the second function
y=2^x:

When
x=0


y=2^x\\ y=2^0\\ y=1

When
x=1


y=2^x\\ y=2^1\\ y=2

When
x=2


y=2^x\\y=2^2\\ y=2^2\\ y=4

User Mesqueeb
by
8.3k points
4 votes

ANSWER

When x=1,
y =2{x}^(2) is 2

and
y = {2}^(x) is 2

When x=2,
y =2{x}^(2) is 8

and
y = {2}^(x) is 4

EXPLANATION

The given functions are:


y =2{x}^(2)

and


y = {2}^(x)

We want to find the functional values for the given x-values.

When x=1,


y = 2( {1})^(2) = 2

and


y = {2}^(1) = 2

When x=2,

The first function gives us:


y = 2 {(2)}^(2) = 8

and the second function gives


y = {2}^(2) = 4

User Cheborra
by
8.5k points

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