Question

Help me please asappp!!!!​

Answer 1

For the function
`y=2x^2`:

`y=0\\y=2\\y=8`

For the second function
`y=2^x`:

`y=1\\y=2\\y=4`

Explanation:

You only need to make the following substitution:

For the first function
`y=2x^2`:

When
`x=0`

`y=2x^2\\ y=2(0)^2\\ y=0`

When
`x=1`

`y=2(1)^2\\ y=2(1)^2\\ y=2`

When
`x=2`

`y=2x^2\\ y=2(2)^2\\ y=2*4\\ y=8`

For the second function
`y=2^x`:

When
`x=0`

`y=2^x\\ y=2^0\\ y=1`

When
`x=1`

`y=2^x\\ y=2^1\\ y=2`

When
`x=2`

`y=2^x\\y=2^2\\ y=2^2\\ y=4`

Answer 2

When x=1,
`y =2{x}^(2)` is 2

and
`y = {2}^(x)` is 2

When x=2,
`y =2{x}^(2)` is 8

and
`y = {2}^(x)` is 4

EXPLANATION

The given functions are:

`y =2{x}^(2)`

and

`y = {2}^(x)`

We want to find the functional values for the given x-values.

When x=1,

`y = 2( {1})^(2) = 2`

and

`y = {2}^(1) = 2`

When x=2,

The first function gives us:

`y = 2 {(2)}^(2) = 8`

and the second function gives

`y = {2}^(2) = 4`