Hello!
The answer is:
The equation is:
![Total(t)=5200*(2)^(t)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4mk5bgq3pmqzrwfhi6ghmha8js32z96dfu.png)
Why?
It's an exponential growth problem, we can calculate the exponential growth using the following equation:
![Total(t)=StartPopulation*(1+r)^{(t)/(2)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/lhliwxsv45o1qzxsetrbyze3hppdhiubds.png)
Where,
Total, is the total population after "t" time in days.
Start population, for this is equal to 5,200
r,is equal to the percent of growth, for this case it's 100% each day.
t, is the time elapsed.
So, rewriting the equation, we have:
![Total(t)=5200*(1+(100)/(100))^(t)](https://img.qammunity.org/2020/formulas/mathematics/high-school/lkobn8pew2wjunnfiake2dkax4w7bn0smq.png)
![Total(t)=5200*(1+1)^(t)](https://img.qammunity.org/2020/formulas/mathematics/high-school/wbbklw9ke00es3yx4z0gdl18nkb2kr5g4b.png)
![Total(t)=5200*(2)^(t)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4mk5bgq3pmqzrwfhi6ghmha8js32z96dfu.png)
Have a nice day!