Question

What is the equation of the line through (1, 6) and (0, 2)?

Y=4x - 2

Y= -4x - 2

Y= -4x + 2

Y= -4x + 2

Answer 1

y = 4x+2

Explanation:

The first step is to find the slope

m = ( y2-y1)/(x2-x1)

m = ( 2-6)/(0-1)

= -4/-1

= 4

The slope intercept form of the equation is

y = mx+b where m is the slope and b is the y intercept

y = 4x+b

The y intercept is where x is equal to 0

The y intercept is 2

y = 4x+2

Answer 2

Answer: Y = 4x + 2

(It would be either the third or fourth choice since they are the same, one of them must be mistaken)

Explanation:

Given information

(x₁, y₁) = (1, 6)

(x₂, y₂) = (0, 2)

Find the slope through the formula

`Slope~=~(y_2~-~y_1)/(x_2~-~x_1)`

`\Large Slope~=~(2~-~6)/(0~-~1)`

`\Large Slope~=~(-4)/(-1)`

`\Large Slope~=~4`

Substitute values into the linear form

Equation: y = mx + b

Point (0, 2)

y = mx + b

(2) = (4) (0) + b

2 = 0 + b

b = 2 - 0

b = 2

Therefore, the equation is
`\Large\boxed{y=4x+2}`

Hope this helps!! :)

Please let me know if you have any questions