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A gas occupies 65 mL at a temperature of 92.4 °C. What is the volume at 87.6 °C?

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Answer:

64.15 mL.

Step-by-step explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have two different values of V and T:

V₁T₂ = V₂T₁

V₁ = 65.0 mL, T₁ = 92.4°C + 273 = 365.4 K.

V₂ = ??? mL, T₂ = 87.6°C + 273 = 360.6 K.

∴ V₂ = V₁T₂/T₁ = (65.0 mL)(360.6 K)/(365.4 K) = 64.15 mL.

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