Question

Find the roots of the equation below. 7x^2 + 1 = 0

Answer 1

Explanation:

Rewrite 7x^2 + 1 = 0 as 7x^2 = - 1, and then as x^2 = -1/7.

Taking the square root of both sides, and remembering that the square root of a negative number is imaginary, we get:

i√7

x = ±i(1/7) = ± ----------

7

Answer 2

7x2-1 = 0

Explanation:

Add 1 to both sides of the equation :

7x2 = 1

Divide both sides of the equation by 7:

x2 = 1/7 = 0.143

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

x = ± √ 1/7