Question

Find the values for c and d that would make the following equation true. (cy^2)(4y^d)=-20y^3

Answer 1

c = -5 and d = 1

Explanation:

First, multiply out (cy^2)(4y^d). We get: 4cy^(2+d).

We equate this result to the right side of the equation: - 20y^3.

Then, equating the exponents and solving for d, we get: 2 + d = 3, or d = 1.

Equating the coefficients, we get 4c = -20, or c = -5.