Answer:
Part 1)
![z=4√(3)\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xojb6ctaj6azm7jvlm7ywxlcbjaj5qlt2f.png)
Part 2)
![y=4√(2)\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/78yg1zzgy44jw39an37j0yzl5c24b888dg.png)
Part 3)
![x=4√(6)\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6mgcinm8ld94iffsyask9qhr48nu5u70qs.png)
Explanation:
see the attached figure with letters to better understand the problem
step 1
Find the value of z
In the right triangle DBC
----> equation A
In the right triangle ABC
----> equation B
equate equation A and equation B
![(4)/(z)=(z)/(12)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/52t9gntaq8mtpoxozg5bkre00gme2g3eu0.png)
![z^(2)=48](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vycyz5x46mie3udll9t0xtfy6m9rzv55l4.png)
![z=4√(3)\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xojb6ctaj6azm7jvlm7ywxlcbjaj5qlt2f.png)
step 2
In the right triangle DBC
Applying the Pythagoras Theorem
![z^(2)=y^(2)+4^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fikmk4kt6tacoucj6zqrqra2okp7k7nakz.png)
we have
![z=4√(3)\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xojb6ctaj6azm7jvlm7ywxlcbjaj5qlt2f.png)
substitute
![(4√(3))^(2)=y^(2)+4^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5k0wls4svcsl14afywrp59o9qgcn64tont.png)
![48=y^(2)+16](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d3sbyiux8ibz1aa3266q3r5ffheg3f6eg7.png)
![y^(2)=48-16](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3h152cixek8ndyddf53jc7h630zrmnovha.png)
![y^(2)=32](https://img.qammunity.org/2020/formulas/mathematics/middle-school/spmx7blrbwxrqm16c46nehb1tb69bgnrkt.png)
![y=4√(2)\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/78yg1zzgy44jw39an37j0yzl5c24b888dg.png)
step 3
Find the value of x
In the right triangle ABC
Applying the Pythagoras Theorem
![12^(2)=x^(2)+z^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ia3rtmz29zlrqiccm28b0lvx0sisfidwa6.png)
we have
![z=4√(3)\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xojb6ctaj6azm7jvlm7ywxlcbjaj5qlt2f.png)
substitute
![12^(2)=x^(2)+(4√(3))^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rs8gdg3hev2dded2ipemzg4xn7n18fe9gn.png)
![144=x^(2)+48](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hwv9dv62wuvihxubnfv4bvfoyr7pwxozjt.png)
![x^(2)=144-48](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ajvcravt54e2vbypc17vf17s6tshbbm58z.png)
![x^(2)=96](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dotroi8woc0dvxav81qc4h6c2yc4780ynp.png)
![x=4√(6)\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6mgcinm8ld94iffsyask9qhr48nu5u70qs.png)