Question

Plsssss helpppp teacher won’t helppp

Answer 1

A. The graphs of two of the functions have a minimum point.

Explanation:

Option A is false, because the only function that has a minimum point is

`h(x)=(1)/(4)x^2+1`

Option B is true because all the functions are of the form;

`y=ax^2+c`

The equation of axis of symmetry of equations in this form is x=0.

Option C is also true because,
`h(x)=(1)/(4)x^2+1` is a minimum graph and its y-intercept is 1. This graph will hang above the x-axis.

`g(x)=-2x^2-5` is a maximum graph whose y-intercept is -5.

This graph also hangs below the x-axis.

Option D is also true. The y-intercepts are 6,-5, and 1