Question

What is 3log2x-(log2(x+4)) written as a single logarithm

Answer 1

c

Explanation:

Answer 2

`\large\boxed{3\log_2x-\log_2(x+4)=\log_2(x^3)/(x+4)}`

Explanation:

`3\log_2x-\log_2(x+4)\\\\\text{use}\ \log_ab^n=n\log_ab\ \text{and}\ \log_ab-\log_ac=\log_a(b)/(c)\\\\=\log_2x^3-\log_2(x+4)=\log_2(x^3)/(x+4)\\\\\text{Domain:}\\\\x>0\ \wedge\ x+4>0\to x>0\ \wedge\ x>-4\\\\\boxed{x>0}`