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The inequality -x^2 -6 <0 has how many critical points

User Kim Stebel
by
7.7k points

2 Answers

3 votes

Answer:

See below.

Explanation:

This inequality is < 0 for all real values of x. We see this by solving -x^2 - 6 = 0 for x:

-x^2 - 6 = 0

-x^2 = 6

x^2 = -6 for which there are no real solutions of x. So the graph does not pass through the x axis.

At x = 0. f(x) < -6 so that is the one critical value - all values of f(x) are below this value.

User Sam Alba
by
8.4k points
3 votes

Answer:

0 critical points

Explanation:

Just did it and got it right

User Fulkron
by
8.2k points

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