Question

Carbon disulfide burns with oxygen to form carbon dioxide and sulfur dioxide in the following manner: CS2 + 3O2 → CO2 + 2SO2

What is the volume of sulfur dioxide (SO2 gas), formed when 2 moles of carbon disulfide (CS2) are burned? The reaction is taking place at STP.

5.6 L
22.4 L
89.6 L
44.8 L

Answer 1

89.6 L.

Step-by-step explanation:

Answer 2

89.6 L.

Step-by-step explanation:

• For the balanced reaction:

CS₂ + 3O₂ → CO₂ + 2SO₂.

• It is clear that 1.0 mole of CS₂ with 3.0 moles of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.

Using cross multiplication:

1.0 mole of CS₂ produces → 2.0 moles of SO₂.

2.0 mole of CS₂ produces → ??? moles of SO₂.

∴ The no. of moles of SO₂ produced = (2.0 mol)(2.0 mol)/(1.0 mol) = 4.0 mol.

• It is known that 1.0 mole of any gas at STP occupies 22.4 L.

∴ 4.0 moles of SO₂ occupy = (4.0)(22.4 L) = 89.6 L.