Answer:
1.25 focal lengths
Step-by-step explanation:
The lens equation states that:
![(1)/(f)=(1)/(p)+(1)/(q)](https://img.qammunity.org/2020/formulas/physics/high-school/n7woqmvve1hantxzvmg5itsbubgjrzuc3a.png)
where
f is the focal length
p is the object distance
q is the image distance
In this problem, the image is 4 times as far from the lens as is the object: this means that
![q=4p](https://img.qammunity.org/2020/formulas/physics/high-school/ba7g9kdj88fo7x3f5buuk02lnfprw9nee5.png)
If we substitute this into the lens equation and we rearrange it, we get
![(1)/(f)=(1)/(p)+(1)/(4p)=(4+1)/(4p)=(5)/(4p)\\p=(5)/(4)f=1.25 f](https://img.qammunity.org/2020/formulas/physics/high-school/mgrrwz61nlhwq9d21dbwauhfao3m85mlii.png)
so, the object distance measured in focal lengths is
1.25 focal lenghts