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44 votes
44 votes
Find the area of the irregular figure.

6 in.
13 in.
12 in.
5 in.
4 in.
4 in.
A = [? ]in.² please explain why or how you got the answer for future questions I only have so many points

Find the area of the irregular figure. 6 in. 13 in. 12 in. 5 in. 4 in. 4 in. A = [? ]in-example-1
User Borka
by
2.8k points

1 Answer

20 votes
20 votes

Answer:

153 in²

Explanation:

Area of irregular figure


\sf \boxed{\text{\bf Area of rectangle = length * width}}


\sf \boxed{\text{\bf Area of square = side *side}}

Figure I:

length = 12 in

width = 6 in

Area of figure I = 12 * 6

= 72 in²

Figure II:

length = 13 in

width = 5 in

Area of figure II = 13 * 5

= 65 in²

Figure III:

side = 4 in

Area of figure III = 4 * 4

= 16 in²

Area of irregular shape = 72 + 65 + 16

= 153 in²

Find the area of the irregular figure. 6 in. 13 in. 12 in. 5 in. 4 in. 4 in. A = [? ]in-example-1
User Adirmola
by
3.1k points