Question

Please help me
thanks!!

Answer 1

Answer:
`\bold{x=(21)/(4)}`

Explanation:

`(1)/(2)(2x+y)=(21)/(2)\\\\\text{Multiply both sides by 2 to clear the denominator:}\\2x + y = 21\\\\\text{Now, the system is:}\bigg\{{2x+y=21\atop{y=2x}}\\\\\text{Substitute y in the first equation with 2x to solve for x:}\\2x + y = 21\\2x + 2x = 21\\.\qquad 4x=21\\\\.\qquad \large\boxed{x=(21)/(4)}`

Answer: a = 2

Explanation:

`.\quad (2x+6)/((x+2)^2)-(2)/(x+2)\bigg((x+2)/(x+2)\bigg)\\\\\\=(2x+6)/((x+2)^2)+(-2(x+2))/((x+2)^2)\bigg\\\\\\\\=(2x+6-2x-4)/((x+2)^2)\\\\\\=(2)/((x+2)^2)\implies \large\boxed{a=2}`

Answer 2

Explanation:

Question One

Multiply through by 2

2*1/2 * (2x + y ) = 21/2 * 2

Combine

2x + y = 21

Subtract 2x from both sides

y = 21 - 2x

Now equate the two given equations

y = 21 - 2x

y = 2x

Add 2x to both sides

2x = 21 - 2x

2x + 2x = 21

4x = 21

x = 21/4

x = 5 1/4

or

x = 5.25

Question 2

`(2x + 6)/((x + 2)^2) - (2)/((x + 2))`

multiply numerator and denominator of the second fraction by (x + 2)

`(2x + 6)/((x + 2)^2) - (2(x + 2))/((x + 2)*(x + 2))`

Remove the numerator brackets in the right hand fraction. Look out for the minus sign.

`(2x + 6)/((x + 2)^2) - (2(x + 2))/((x + 2)^2)\\\\(2x + 6- 2x - 4)/((x + 2)^2)}\\\\(2)/((x + 2)^2)`