Question

How do you solve 3x+1 = 15 for x using the change of base formula log base b of y equals log y over log b?

Answer 1

Anwser is 14/3

Subtract the 1 and divide by 3

Answer 2

Answer with explanation:

The given equation in single variable x, is

⇒3 x+1=15

Subtracting 1 from both sides

⇒ 3 x +1 -1 = 15- 1

⇒3 x =14

Dividing both sides by, 3 we get

`x=(14)/(3)\\\\x=log_(10)(14)/(3)\\\\ \log_(a)b=(\log b)/(\log a)`

Because ,log 10=1