Question

A model electric train requires 3.7267 V to operate. If the primary coil of its transformer has 184.463 turns windings, how many windings should the secondary have if the primary is connected to a 100.864 V household circuit? Answer in units of turns.

Answer 1

= 6.815 turns

Step-by-step explanation:

From the Turn ratio equation;

Ns/Np= Vs/Vp

Where; Ns and Np is the number of turns in the secondary and primary coil respectively.

Vs and Vp are the voltages in the secondary and primary coils respectively.

Since; Vs = 3.7267 V, Vp = 100.864 V, Ns =? and Np =184.463 turns

Thus;

Ns = (Np× Vs)/Vp

=(184.463×3.7267)/100.864

= 6.815 turns

Therefore, the number of windings in the secondary coil should be 6.815 turns.