The temperature of the cosmic background radiation is measured to be 2.7 k. What is the wavelength of the peak in the spectral distribution at this temperature?

Question

asked Aug 19, 2020 197k views

1 Answer

Csano · Answer 1 · 2020-08-23T05:04:58+0000

Answer:

$1.07\cdot 10^(-3) m$

Step-by-step explanation:

The peak wavelength of the spectral distribution can be found by using Wien's displacement law:

$\lambda=(b)/(T)$

where

$b=2.898\cdot 10^(-3) m\cdot K$ is Wien's displacement constant

T is the absolute temperature

For the cosmic background radiation, the temperature is

T = 2.7 K

So, the corresponding peak wavelength is

$\lambda=(2.898\cdot 10^(-3) m\cdot K)/(2.7 K)=1.07\cdot 10^(-3) m$