Question

The temperature of the cosmic background radiation is measured to be 2.7 k. What is the wavelength of the peak in the spectral distribution at this temperature?

Answer 1

`1.07\cdot 10^(-3) m`

Step-by-step explanation:

The peak wavelength of the spectral distribution can be found by using Wien's displacement law:

`\lambda=(b)/(T)`

where

`b=2.898\cdot 10^(-3) m\cdot K` is Wien's displacement constant

T is the absolute temperature

For the cosmic background radiation, the temperature is

T = 2.7 K

So, the corresponding peak wavelength is

`\lambda=(2.898\cdot 10^(-3) m\cdot K)/(2.7 K)=1.07\cdot 10^(-3) m`