Answer:
$7.30
Explanation:
The problem statement gives rise to two equations:
- 3a +2c = 33.50
- 1a +4c = 30.50
If we double the first equation and subtract the second, we have ...
2(3a +2c) -(1a +4c) = 2(33.50) -(30.50)
5a = 36.50 . . . . simplify
a = 7.30 . . . . . . .divide by 5
The cost of one adult ticket is $7.30.