Question

Hte area of a rectangle trampoline is 112 ft^2. the length of the trampoline is 6ft greater than the width of the trampoline, this situation can be represented by the equation w^2+6w-112=0

what is the lengeth of the trampoline in feet?
7
16
8
14

Answer 1

Explanation:

alright, lets get started.

suppose the width is w.

the length is 6 feet greater than the width, so

length will be = w+6

area of the trampoline = length*width

`area=(w+6)*w = w^2 +6w`

as per given, area is 112, so

`w^2+6w=112`

subtracting 112 in both sides

`w^2+6w-112=0`

factoring

`(w-8)(w+14)=0`

So, it will give two values of w

w=8 and w = -14

The width can't be negative, so

width = 8 feet. : answer

Hope it will help :)