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Which statement about g(x)=x^2-576 is true

a. the zeros, -288 and 288, can be found when 0=(x+288)(x-288.
b. the only zero,288 , can be found when 0=(x-288)^2.
c. the zeros, -24 and 24, can be found when 0= (x+24)(x-24).
d. the only zero, 24, can be found when 0=(x-24)^2

User Schluchc
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2 Answers

4 votes

Answer:

The zeros, -24 and 24, can be found when 0= (x+24)(x-24).

Explanation:

User David Chase
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5.5k points
6 votes

Answer:

c. the zeros, -24 and 24, can be found when 0= (x+24)(x-24).

Explanation:

The given function is


g(x)=x^2-576

When we equate the function to zero, we obtai;


x^2-576=0

Use difference of two squares:


x^2-24^2=0


(x-24)(x+24)=0

Use the zero product property to obtain;


x-24=0,\:and\:x+24=0

This implies that;


x=24,\:and\:x=-24

The correct choice is C

User Hammad Ahmed Khan
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5.9k points