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The length of a rectangle is five times its width.

if the area of the rectangle is 320 yd^2, find its perimeter.
? yd

User Jmz
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ANSWER

96 yd

Step-by-step explanation

Let the width of the rectangle be w, then, the length of the rectangle will be:


l = 5w

The area of a rectangle is calculated using the formula:


Area=l * w


Area=5w * w


Area=5 {w}^(2)

It was given that, the area of the rectangle is 320yd²


320=5 {w}^(2)

Divide both sides by 5.


64 = {w}^(2)

Take square root of both sides to get:


w = 8yd

This means the length is


l = 5 * 8 = 40yd

The perimeter of a rectangle is given by:

P=2(w+l)

We plug in the values to get:


P=2(40 + 8) = 2 * 48 = 96yd

The perimeter is 96yd

User Baskettaz
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