Question

The length of a rectangle is five times its width.

if the area of the rectangle is 320 yd^2, find its perimeter.
? yd

Answer 1

96 yd

Step-by-step explanation

Let the width of the rectangle be w, then, the length of the rectangle will be:

`l = 5w`

The area of a rectangle is calculated using the formula:

`Area=l * w`

`Area=5w * w`

`Area=5 {w}^(2)`

It was given that, the area of the rectangle is 320yd²

`320=5 {w}^(2)`

Divide both sides by 5.

`64 = {w}^(2)`

Take square root of both sides to get:

`w = 8yd`

This means the length is

`l = 5 * 8 = 40yd`

The perimeter of a rectangle is given by:

P=2(w+l)

We plug in the values to get:

`P=2(40 + 8) = 2 * 48 = 96yd`

The perimeter is 96yd