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How do you solve this question? Differentiate:


x √(x) - {x}^(2) √(x)


User Dan Gayle
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1 Answer

6 votes

Answer:


\displaystyle (d)/(dx)[x√(x)-x^(2)√(x)]


\displaystyle =(3)/(2)√(x) - (5)/(2)\;x√(x)

Explanation:

There's no need for the product rule. Consider the following:


  • √(x) is the same as
    x^(1/2)

As a result,


  • x√(x) = x\cdot x^(1/2) = x^(3/2), and

  • x^(2)√(x) = x^(2)\cdot x^(1/2) = x^(5/2).


\displaystyle x√(x)-x^(2)√(x) = x^(3/2) - x^(5/2).

How to differentiate the first term,
x^(3/2)?

Apply the power rule.


\displaystyle (d)/(dx) [x^(3/2)] = \underbrace{3/2}_{\begin{aligned}&\text{from}\\[-0.5em]& \text{power}\end{aligned}} \;x^((3/2) - 1) = (3)/(2)\;x^(1/2).


\displaystyle (d)/(dx) [x^(5/2)] = \underbrace{5/2}_{\begin{aligned}&\text{from}\\[-0.5em]& \text{power}\end{aligned}} \;x^((5/2) - 1) = (5)/(2)\;x^(3/2).

The derivative of difference is the difference of derivatives. Rewrite
x^(1/2) back as
√(x) since the question uses square roots rather than fraction power.


\displaystyle\begin{aligned} (d)/(dx)[x√(x)-x^(2)√(x)] &=(d)/(dx)[x√(x)] - (d)/(dx)[x^(2)√(x)] \\&=(3)/(2)\;x^(1/2) - (5)/(2)\;x^(3/2)\\ &=(3)/(2) √(x) - (5)/(2) x√(x)\end{aligned}.

User CherryQu
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