Question

How many moles of NaCl are present in 2.50 L of a 0.070 M solution?

a

2.8 x 10-2 moles of NaCl


b

35.7 moles of NaCl

c

1.75 x 10-4 moles of NaCl


d

0.175 moles of NaCl

Answer 1

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

`M = (n)/(V(in\ L))`

So,

`n = M * V\\\\n = 0.070* 2.5 \\\\n = 0.175\ moles`

Therefore, number of moles of NaCl is 0.175 moles.