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The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball in the room in a shot in which the ball goes exactly in the center of the room? Show your work

Thanks so much in advance ! :))

User MattjeS
by
5.6k points

1 Answer

2 votes

Answer:

The distance between the ball in the room is
4.2\ in

Explanation:

We know that for a circumference the radius is equal to half the diameter.


r =(d)/(2)

The diameter of the basketball hoop is 18 inches.

Then the radius of the hoop is:


r = (18)/(2)\\\\r = 9\ inches

If, the circumference of the ball is 30 inches then the circumference C is:


C = 2(\pi)r=30

And the radius of the ball is:


30 = 2(\pi)r\\\\r =(15)/(\pi)

So the distance between the ball and the ring will be equal to the difference of both radius.


k = 9-(15)/(\pi)\\\\k = 4.2\ in

User Panduka DeSilva
by
4.8k points
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